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标题 python列表操作实例
范文
    本文实例讲述了python列表操作的方法。分享给大家供大家参考。
    具体实现方法如下:
    复制代码 代码如下:class Node:
    """Single node in a data structure"""
    def __init__(self, data):
    """Node constructor"""
    self._data = data
    self._nextNode = None
    def __str__(self):
    """Node data representation"""
    return str(self._data)
    class List:
    """Linked list"""
    def __init__(self):
    """List constructor"""
    self._firstNode = None
    self._lastNode = None
    def __str__(self):
    """List string representation"""
    if self.isEmpty():
    return "empty"
    currentNode = self._firstNode
    output = []
    while currentNode is not None:
    output.append(str(currentNode._data))
    currentNode = currentNode._nextNode
    return " ".join(output)
    def insertAtFront(self, value):
    """Insert node at front of list"""
    newNode = Node(value)
    if self.isEmpty(): # List is empty
    self._firstNode = self._lastNode = newNode
    else: # List is not empty
    newNode._nextNode = self._firstNode
    self._firstNode = newNode
    def insertAtBack(self, value):
    """Insert node at back of list"""
    newNode = Node(value)
    if self.isEmpty(): # List is empty
    self._firstNode = self._lastNode = newNode
    else: # List is not empty
    self._lastNode._nextNode = newNode
    self._lastNode = newNode
    def removeFromFront(self):
    """Delete node from front of list"""
    if self.isEmpty(): # raise exception on empty list
    raise IndexError, "remove from empty list"
    tempNode = self._firstNode
    if self._firstNode is self._lastNode: # one node in list
    self._firstNode = self._lastNode = None
    else:
    self._firstNode = self._firstNode._nextNode
    return tempNode
    def removeFromBack(self):
    """Delete node from back of list"""
    if self.isEmpty(): # raise exception on empty list
    raise IndexError, "remove from empty list"
    tempNode = self._lastNode
    if self._firstNode is self._lastNode: # one node in list
    self._firstNode = self._lastNode = None
    else:
    currentNode = self._firstNode
    # locate second-to-last node
    while currentNode._nextNode is not self._lastNode:
    currentNode = currentNode._nextNode
    currentNode._nextNode = None
    self._lastNode = currentNode
    return tempNode
    def isEmpty(self):
    """Returns true if List is empty"""
    return self._firstNode is None
    希望本文所述对大家的Python程序设计有所帮助。
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更新时间:2025/5/23 0:47:31