| 标题 | JS实现图片平面旋转的方法 |
| 范文 | 本文实例讲述了JS实现图片平面旋转的方法。分享给大家供大家参考，具体如下： <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>图片旋转</title> <style type="text/css" > #div1{ position:relative;height:800px; border:1px solid red;} #div1 img{ position:absolute;} </style> </head> <body > <div id="div1" > <img src="/uploads/202504/02/logo2826.gif" /> <img src="/uploads/202504/02/logo2826.gif" /> <img src="/uploads/202504/02/logo2826.gif" /> <img src="/uploads/202504/02/logo2826.gif" /> <img src="/uploads/202504/02/logo2826.gif" /> <img src="/uploads/202504/02/logo2826.gif" /> </div> <script type="text/javascript" > var centerx = 400; //圆心X var centery = 300; //圆心Y var r = 300; //半径 var oimages = document.getElementById("div1").getElementsByTagName("IMG"); //图片集合 var cnt = oimages.length; //图片数 var da = 360 / cnt; //图片间隔角度 var a0 = 0; //已旋转角度 var timer; for (var i = 0; i < cnt; i++) { oimages[i].onmouseover = stop; oimages[i].onmouseout = start; } function posimgs() { for (var i = 0; i < cnt; i++) { oimages[i].style.left = centerx + r * Math.cos((da * i + a0) / 180 * Math.PI) + "px"; oimages[i].style.top = centery + r * Math.sin((da * i + a0) / 180 * Math.PI) + "px"; } } // posimgs(); function start() { timer = window.setInterval("posimgs();a0++;", 100); } function stop() { window.clearInterval(timer); } start(); </script> </body> </html> 希望本文所述对大家JavaScript程序设计有所帮助。 |
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